If a,b,c are in HP and ab bc ca = 15 then ca = Since a,b,c are in harmonic progression, their reciprocals ,, form an arithmetic sequence Let d be the common difference Then Solve each for d Since both equal d, they are equal to each other Multiply through by LCD of abc ac bc = ab ac 2ac = ab bc And since we are given that ab bc ca Hints Start with ( a b c )^2 and establish the inequality ( a b c )^2 0 I haven't make much progress I've been trying;Now substitute these value in ABC= 15 From above choices the no 8,2,5 satisfy above equation Now we will satisfy these value in other equation Let A = 8 B= 2 C=5 It will satisfy the equation AB BCCA= 66 Hence value of A=8, B= 2 , C= 5 Or it can be A=2, B=8, C=5 Or it can be A=5, B=8, C=2 And there can be many more possibilities
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Ab bc ca if a b c=15 and a^(2) b^(2) c^(2)=77
Ab bc ca if a b c=15 and a^(2) b^(2) c^(2)=77-In right triangle ABC, AC = x, BC = x 1, and hypotenuse AB = 2x 1 Find the length of AC only' Using pythag a^2 b^2 = c^2, where s Cho a b c > 0 và ab bc ca = 1,Chứng minh S = a/căn(1 a^2) b/căn(1 b^2) c/căn(1 c^2) = 3/2 Like và Share Page Lazi để đón nhận được nhiều thông tin thú vị và bổ ích hơn nữa nhé!
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👍 Correct answer to the question (ii) find ab bc ca if a b c = 15 anda b² c ² = 77 eanswersinLeast Common Multiple (ab) • (bc) Calculating Multipliers 102 Calculate multipliers for the two fractions Denote the Least Common Multiple by LCM Denote the Left Multiplier by Left_M Denote the Right Multiplier by Right_M Denote the Left Deniminator by L_Deno Denote the Right Multiplier by R_Deno Left_M = LCM / L_Deno = bc If a b c = 5 and a^2 b^2 c^2 = 29 then find the value of ab bc ca
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Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries Students (upto class 102) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (MainsAdvance) and NEET can ask questions from any subject and get quick answers byBy taking LCM we get = (ab bc ca)/ (abc) (abc) put, abbcca=0 you get value = 0/ (abc) (abc) = 0 MOHIT LADIA 13 Points 4 years ago Take a=b=1 and get the value of c , so you will get c=1/2 put the value of a=b=1 and c=1/2 in the equation on the right hand side , you will get ans as 0You can put this solution on YOUR website!
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If abc=9 and abbcca=26 find a2b2c2 Ask questions, doubts, problems and we will help you menu myCBSEguide Courses CBSE Entrance Exam Competitive Exams ICSE & ISC Teacher Exams UP Board Uttarakhand Board Features OnlineStack Exchange network consists of 178 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers Visit Stack ExchangeIf a b c = 13, a2 b2 c2 = 69 then find the ab bc ca A) 10 B) 30 C) 50 D) 70 Answer C) 50 Explanation (a b c)2 = a2 b2 c2 2(ab bc ca) Subject Simplification Quantitative Aptitude Arithmetic Ability
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Simple and best practice solution for (abc)(bccaab)=9abc equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve it (a b) 2 = a 2 b 2 2ab (a − b) 2 = a 2 b 2 − 2ab a 2 − b 2 = (a − b) (a b) (x a) (x b) = x 2 (a b) x ab (a b c) 2 = a 2 b 2 c 2(abbcca)² = (ab) ²(bc)²(ca)²2(ab)(bc)2(bc)(ca)2(ca)(ab) hence, (ab)²(bc)²(ca)²2ab²c2abc²2a²bc (ab)²(bc)²(ca)²2abc(bca)
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3 a) truth table b) sop y0 = (a'b'c'd)(a'b'cd')(a'bc'd')(a'bcd)(ab'c'd')(ab'cd)(abc'd)(a bcd') y1= (a'b'cd)(a'bc'd Example 16 If A = 8(1&1&−1@2&0&3@3&−1&2), B = 8(1&3@0&2@−1&4) and C = 8(1&2&3&−4@2&0&−2&1), find A(BC), (AB) C and show that (AB) C = A (BC) For A =>v=2ab2ca2bc =>2ab2ca=v2bc =>2a(bc)=v2bc =>a=(v2bc)/((2(bc))
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( a b c )^2 = a^2 b^2 c^a 2ab 2bc 2caCorrect answer to the question If abc =10 and abbcca=15 find (abc)(a^2b^2c^2abbcca) studyassistantincomMath, 1850, piyush If abc=6 and abbccan=15;then a/2b/2c/2=
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Example Solve 8a 3 27b 3 125c 3 – 90abc Solution This proceeds as Given polynomial (8a 3 27b 3 125c 3 – 90abc) can be written as (2a) 3 (3b) 3 (5c) 3 – 3(2a)(3b)(5c) And this represents identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3 Given, a b c = 15 and a 2 b 2 c 2 = Now, a 3 b 3 c 3 3abc = (a b c) (a 2 b 2 c 2 ab bc ca) Again, (a b c) 2 = a 2 b 2 c 2 2ab 2bc 2caSolutionShow Solution Recall the formula ` (abc)^2 = a^2 b^2 c^2 2 (ab bc ca)` Given that `a^2 b^2 c^2 = 250 , ab bc ca = 3 ` Then we have ` (abc)^2 = a^2 b^2 c^2 2 (ab bcca)` ` (abc)^2 = 250 2 (3)` ` (abc)^2 = 256`
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If `abc=2` and `abbcca=1` then find `(ab)^2(bc)^2(ca)^2` Step by step solution by experts to help you in doubt clearance & scoring excellent marks in examsA 2 b 2 c 2 2 × 59 = 625 Given, ab bc ca = 59 a 2 b 2 c 2 118 = 625 a 2 b 2 c 2 118 – 118 = 625 – 118 subtracting 118 from both the sides Therefore, a 2 b 2 c 2 = 507 Thus, the formula of square of a trinomial will help us to expand 7th Grade Math Problems 8th Grade Math Practice From Square of a Trinomial toTo ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If `b^2c^2,ab,ac , ba,c^2a^2,bc , ca,cb,a^2b^2`= a square of a determ
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Find the value of ab bc ca if , a b c = 15 and tex {a}^{2} {b}^{2} {c}^{2} is = 77/texP Get the answers you need, now!If A 2 B 2 C 2 1 Then Ab Ca Lies In The Interval Youtube Save Image A B C 0 Prove B2 Ac C2 Ab 3 Brainly In Save Image In Any Triangle Abc Prove That Asin B C B 2 C 2 Bsin C A C 2 A 2 Csin A B A 2 B 2 Save Image If Math A B C 1 Math Math A 2 B 2 C 2 2 Math And Math A 3 B 3 C 3 3 Math Then What Is Math A Times B Times C Math QuoraIf a 2 b 2 c 2 abbcca=0 then prove that a=b=c Hello student, Please find the answer to your question below a² b² c² = ab bc ca Mult
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A question on finding maximum This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges Explanations are more than just a solution — they should explain the steps and thinking strategies that you used toThe important thing to notice is that all three expressions are symmetric polynomials, ie, each variable appears an equal number of times and swapping any two terms doesn't change the result The two expressions abc and abacbc are a subtype called elementary symmetric polynomials, whose summands only include each variable once The expression a²b²c² is a different2nd Floor, Above Ghanshyam Super Market,Botanical Gardens Road, Sri Ramnagar Block B,Kondapur Hyderabad () support@crackuin 91 630 323 9042
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If a b c = 6 and ab bc ca = 10, then value of a3 b3 c3 3abc is a) 36 b) 48 c) 42 d) 40 Solution(By Examveda Team) Given , a b c = 6 ab bc ca = 10 ∴ (a b c) 2 = 36 ⇒ a 2 b 2 c 2 2ab 2bc 2ca = 36 ⇒ a 2 b 2 c 2 2(ab bc ca) = 36 ⇒ a 2 b 2 c 2 2 × 10 = 36 ⇒ a 2 b 2 c 2 = 16 As we knowSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more If abc=6 and abbcca=11, find the value of a 3 b 3 c 33abc Share with your friends Share 37 Given, a b c = 6 and ab bc ca = 11 Now, a 3 b 3 c 3 3abc = (a b c) (a 2 b 2 c 2 ab bc ca) Again, (a b c) 2 = a 2 b 2 c 2 2ab 2bc 2ca
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If a b c = 9 and ab bc ca = 26, find a2 b2 c2 If a b c = 9 and ab bc ca = 26, find a 2 b 2 c 2In an examination in which the full marks were 500, A scored 25% more marks than B, B scored 60% more marks than C and C scored % less marks than D IfA scored 80% marks, then the percentage of marks obtained by is views around the world You can reuse this answer Creative Commons License
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If abc=0, then find the value of a2/bcb2/cac2/ab and this time please explain it properly because last time I could not understand how_to_reg Follow thumb_up Like (14) Subhikshasampath (abc) 2 =a 2 b 2 c 2 2ab2bc2ca a 2 b 2 c 2 = (abc) 2 2ab2bc2ca a 2 b 2 c 2 = (7) 2 2 (abbcca) a 2 b 2 c 2 = (7) 2 2 () a 2 b 2 c 2 = 4940 a2b2c2= 9Least Common Multiple (bc) • (ca) • (ab) Calculating Multipliers 162 Calculate multipliers for the two fractions Denote the Least Common Multiple by LCM Denote the Left Multiplier by Left_M Denote the Right Multiplier by Right_M Denote the Left Deniminator by L_Deno Denote the Right Multiplier by R_Deno Left_M = LCM / L_Deno = ab
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$$ (abc)^2 = a^2 b^2 c^2 2(ab bc ca) $$ The LHS of the above identity is a perfect square, hence it is always positive or 0 Thus, $$ a^2 b^2 c^2 2(ab bc caSolution for abbcca=abc equation Simplifying ab bc ca = abc Reorder the terms ab ac bc = abc Solving ab ac bc = abc Solving for variable 'a' Move all terms containing a to the left, all other terms to the right Add '1abc' to each side of the equation ab ac 1abc bc = abc 1abc Reorder the terms ab 1abc ac bc = abc 1abc Combine like terms abc 1abc = 0 ab 1abc ac bc = 0 Add '1bc' to each side of the equation ab
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